How can I bootstrap Public role to have create permissions?

Questions and Answers
12

Awesome, thanks for helping with that.

I have one more related question tho. What about bootstrapping super admin?
I tried using this script:

const createSuperAdminUser = async () => {
  const params = {
    username:   process.env.ADMIN_USER,
    password:   process.env.ADMIN_PASS,
    firstname:  process.env.ADMIN_USER,
    lastname:   process.env.ADMIN_USER,
    email:      process.env.ADMIN_EMAIL,
    blocked:    false,
    isActive:   true,
  }

  const admins = await strapi.query('user', 'admin').find({ _limit: 1 })
  if (admins.length) {
    console.error(`Admin user already exists: ${admins[0].email}`)
    return
  }

  try {
    // in the admin under services you can find the super admin role
    const superAdminRole = await strapi.admin.services.role.getSuperAdmin()
    // Hash password before storing in the database
    params.roles = [superAdminRole.id]
    params.password = await strapi.admin.services.auth.hashPassword(params.password)
    // Create admin account
    const admin = await strapi.query('user', 'admin').create({...params})
    console.info('Admin account created:', admin)
  } catch (error) {
    console.error(error)
  }
}

But when it gets to

params.roles = [superAdminRole.id]

It fails with:

app | TypeError: Cannot read property 'id' of null
app |     at createSuperAdminUser (/srv/app/config/functions/bootstrap.js:35:36)
app |     at async module.exports (/srv/app/config/functions/bootstrap.js:83:5)
app |     at async Strapi.runBootstrapFunctions (/srv/app/node_modules/strapi/lib/Strapi.js:407:5)
app |     at async Strapi.load (/srv/app/node_modules/strapi/lib/Strapi.js:336:5)
app |     at async Strapi.start (/srv/app/node_modules/strapi/lib/Strapi.js:190:9)

Because:

    const superAdminRole = await strapi.admin.services.role.getSuperAdmin()

Returns null at first startup. Is that normal?