Set permissions programmatically? #6294

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Mcastres216d ago

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Hello @laggingreflex

What you can do is writing this code inside your config/functions/bootstrap.js

"use strict";
/**
 * An asynchronous bootstrap function that runs before
 * your application gets started.
 *
 * This gives you an opportunity to set up your data model,
 * run jobs, or perform some special logic.
 *
 * See more details here: https://strapi.io/documentation/3.0.0-beta.x/concepts/configurations.html#bootstrap
 */
const findPublicRole = async () => {
  const result = await strapi
    .query("role", "users-permissions")
    .findOne({ type: "public" });
  return result;
};

const setDefaultPermissions = async () => {
  const role = await findPublicRole();
  const permissions = await strapi
    .query("permission", "users-permissions")
    .find({ type: "application", role: role.id });
  await Promise.all(
    permissions.map(p =>
      strapi
        .query("permission", "users-permissions")
        .update({ id: p.id }, { enabled: true })
    )
  );
};

const isFirstRun = async () => {
  const pluginStore = strapi.store({
    environment: strapi.config.environment,
    type: "type",
    name: "setup"
  });
  const initHasRun = await pluginStore.get({ key: "initHasRun" });
  await pluginStore.set({ key: "initHasRun", value: true });
  return !initHasRun;
};

module.exports = async () => {
  const shouldSetDefaultPermissions = await isFirstRun();
  if (shouldSetDefaultPermissions) {
    await setDefaultPermissions();
  }
};

It will allow every permissions on all your collection types during the first run of your application.

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